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22/7r^2=616
We move all terms to the left:
22/7r^2-(616)=0
Domain of the equation: 7r^2!=0We multiply all the terms by the denominator
r^2!=0/7
r^2!=√0
r!=0
r∈R
-616*7r^2+22=0
Wy multiply elements
-4312r^2+22=0
a = -4312; b = 0; c = +22;
Δ = b2-4ac
Δ = 02-4·(-4312)·22
Δ = 379456
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{379456}=616$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-616}{2*-4312}=\frac{-616}{-8624} =1/14 $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+616}{2*-4312}=\frac{616}{-8624} =-1/14 $
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